How To Determine Limiting Reactant Given Moles. $\begingroup$ you can already see from your first calculation that ca(no3)2 is the limiting reagent, because you had more moles of na3po4 than ca3(no3)2 and the equation tells us that 3 moles of ca3(no3)2 react with 2 moles of na3po4. (a) if the calculated moles needed is greater than the moles have for a given reactant, then that reactant is the limiting reagent.
0.000609 moles ca3(no3)2, 2/3 x 0.000609 moles na3po4 and the amount of moles napo4 left after the reaction: = 0.875 ÷ 1 = 0.875.
44 Determining The Limiting Reactant Teaching
A value less than the ratio means the top reactant is the limiting reactant. According to the balanced chemical equation, every 2 moles of h 2 will yield 2 moles of h 2 o.